If (An)-%26gt;0 then (1/(An))-%26gt;Infinity
(An) is supposed to be notation for a sequenceThink of an example to show that the following statement is false?
What if you take the zero sequence, where An=0 for all n?
Then there *is no* sequence 1/(An)! ... and so it cannot go anywhere.
The same should work for all sequences (An) that have 0 at any place - at that point, 1/(An) is undefined, and you lose your 1/(An) sequence ...
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